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Math 3a Solving Quadratic Functions


Solving Quadratic Equations

So far, we have only done an example when the value before the x2 isequal to 1. It works exactly the same way though whatever the value is.

eg.
3x2 - 8x + 4 = 0
(The two numbers are -6 and -2)
3x2-6x-2x+4=0
3x(x-2)-2(x-2)=0
(3x-2)(x-2)=0

3x-2=0
3x=2
x=2/3

x-2=0
x=2

Therefore the two solutions here are 2/3 and 2

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