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Online Simulataneous Equation CalculatorSolving Quadratic EquationsLet's have a look at how we solve a quadratic equation: x2-3x+2=0 The easiest way to solve them is to follow certain steps: Step 1 Find two numbers where when they are multiplied together equal the firstnumber (a=1) multiplied by the third number (c=2). These two numbers when addedto each other must also equal the second number (b=-3). In the above example, the solution is -2 and -1. Step 2 Rewrite the original equation splitting the middle part into two using thenumbers which you found in step 1. x2-x-2x+2=0 Step 3 Start to factorise both halves of the equation: x(x-1)-2(x-1)=0 At this point you will know if you are going along the correct track if thefirst bracket is the same as the second bracket. Step 4 Collect everything before each bracket and put it into one bracket andmultiply this bracket by that which is inside the identical brackets: (x-1)(x-2)=0 Step 5 In order for the left side of the equation to be equal to 0, one of the twobrackets must equal 0. So either: a. b Check these answers: 12-(3*1)+2=0 22-(3*2)+2=0 Therefore the possible solutions for the above equation are confirmed to be 1 and 2 |
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